# C Program to calculate Minimum of three numbers

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### Description:

This program accepts Three integers as input and calculates the Minimum number.

### Program :

1. #include<stdio.h>
2. int main()
3. {
4.    int a,b,c,min;
5.    printf(“Enter Three numbers : “);
6.    scanf(“%d%d%d”,&a,&b,&c);
7.    if( (a<b) && (a<c) )
8.    {
9.       min = a;
10.    }
11.    else if(b<c)
12.    {
13.       min = b;
14.    }
15.    else
16.    {
17.       min = c;
18.    }
19.    printf(“Min of %d, %d and %d is : %dn,a,b,c,min);
20.    return 0;
21. }

### Related C Programs: Venkatesh Macha

Hi Guys, I am Venkatesh Macha. I am a programmer and an Open Source enthusiast, Presently working as a Software Engineer. Apart from that, I love to explore new technologies and things.

### 1 Response

1. Barış Çapraz says:

Binary search [int array]

Binary search [int array]

#include

#define TRUE 0
#define FALSE 1

int main(void) {
int array = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
int left = 0;
int right = 10;
int middle = 0;
int number = 0;
int bsearch = FALSE;
int i = 0;

printf("ARRAY: ");
for(i = 1; i <= 10; i++)
printf("[%d] ", i);

printf("nSearch for Number: ");
scanf("%d", &number);

while(bsearch == FALSE && left <= right) {
middle = (left + right) / 2;

if(number == array[middle]) {
bsearch = TRUE;
printf("** Number Found **n");
} else {
if(number < array[middle]) right = middle – 1;
if(number > array[middle]) left = middle + 1;
}
}

if(bsearch == FALSE)
printf("– Number Not found –n");

return 0;
}